(5x+4)(3x^2-19x+20)=0

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Solution for (5x+4)(3x^2-19x+20)=0 equation: 


Simplifying
(5x + 4)(3x2 + -19x + 20) = 0

Reorder the terms:
(4 + 5x)(3x2 + -19x + 20) = 0

Reorder the terms:
(4 + 5x)(20 + -19x + 3x2) = 0

Multiply (4 + 5x) * (20 + -19x + 3x2)
(4(20 + -19x + 3x2) + 5x * (20 + -19x + 3x2)) = 0
((20 * 4 + -19x * 4 + 3x2 * 4) + 5x * (20 + -19x + 3x2)) = 0
((80 + -76x + 12x2) + 5x * (20 + -19x + 3x2)) = 0
(80 + -76x + 12x2 + (20 * 5x + -19x * 5x + 3x2 * 5x)) = 0
(80 + -76x + 12x2 + (100x + -95x2 + 15x3)) = 0

Reorder the terms:
(80 + -76x + 100x + 12x2 + -95x2 + 15x3) = 0

Combine like terms: -76x + 100x = 24x
(80 + 24x + 12x2 + -95x2 + 15x3) = 0

Combine like terms: 12x2 + -95x2 = -83x2
(80 + 24x + -83x2 + 15x3) = 0

Solving
80 + 24x + -83x2 + 15x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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